Projection Under uniform Acceleration
The height y and horizontal distance x covered by a projectile in a time t seconds are given by the equations y = 8t – 5t2 and x = 6t. If x and y are measured in metres, the velocity of projection is
If u be the speed of projection and θ be the angle of projection, then x = (ucosθ)t and
comparing with x = 6t and y = 8t - 5t2, we can write, ucosθ = 6 and usinθ = 8
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