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The height y and horizontal distance x covered by a projectile in a time t seconds are given by the equations y = 8t – 5t2 and x = 6t. If x and y are measured in metres, the velocity of projection is

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answer is 4.

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Detailed Solution

If u be the speed of projection and θ be the angle of projection, then x = (ucosθ)t and comparing with x = 6t and y = 8t - 5t2, we can write, ucosθ = 6 and usinθ = 8

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The height y and horizontal distance x covered by a projectile in a time t seconds are given by the equations y = 8t – 5t2 and x = 6t. If x and y are measured in metres, the velocity of projection is