First slide

Projection Under uniform Acceleration

Question

A helicopter is flying horizontally at 8 m/s at an altitude 180 m when a package of emergency medical supplies is ejected horizontally backward with a speed of 12 m/s relative to the helicopter. Ignoring air resistance what is horizontal distance between the package and the helicopter when the package hits the ground?

Moderate

A

120 m
B

24 m
C

36 m
D

72 m

Solution

Time taken by package to reach the ground:
$T = \sqrt{\frac{2 \times 180}{10}} = 6 s$
Horizontal distance travelled by helicopter in this time:8 x 6 = 48 m.
Velocity of package w.r.t ground = 12-8 = 4 m/s in backward direction.
Horizontal distance travelled by package in time T = 4 $\times 6 = 24 m .$
So horizontal distance between them = 48 +24 = 72 m

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