Q.

Helium and oxygen gases are contained in two identical vessels at temperatures  T0  and  respectively. Their respective pressures are P0 and  4P0. They are  connected  by a thin pipe and are allowed to diffuse without any loss of energy. The equilibrium  pressure of the gaseous mixture is  69P013N. Find N.

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answer is 2.

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Detailed Solution

Let  n1 and n2  be the number of moles of Helium and oxygen gases respectively, and  v0  be volume of each vessel.  Then from equation of staten1=P0V0RT0  and  n2=4P0V0R2T0=2P0V0RT0⇒n2=2n1 If T is the final temperature, then the initial total internal energy (kinetic) of the two  gases must be equal to that of the final mixture.Ui=n13RT02+n25R2T02Uf=n13RT2+n25RT2Ui=Uf gives T=T03n1+10n23n1+5n2=T03n1+20n13n1+10n1=2313T0 The final pressure P will be given byP2V0=n1+n2RT⇒P=n1+n2RT2V0=3n1RT2V0⇒P=3R2V0n1T=3R2V0P0V0RT02313T0=6926P0
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