Q.
Helium and oxygen gases are contained in two identical vessels at temperatures T0 and respectively. Their respective pressures are P0 and 4P0. They are connected by a thin pipe and are allowed to diffuse without any loss of energy. The equilibrium pressure of the gaseous mixture is 69P013N. Find N.
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
answer is 2.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Let n1 and n2 be the number of moles of Helium and oxygen gases respectively, and v0 be volume of each vessel. Then from equation of staten1=P0V0RT0 and n2=4P0V0R2T0=2P0V0RT0⇒n2=2n1 If T is the final temperature, then the initial total internal energy (kinetic) of the two gases must be equal to that of the final mixture.Ui=n13RT02+n25R2T02Uf=n13RT2+n25RT2Ui=Uf gives T=T03n1+10n23n1+5n2=T03n1+20n13n1+10n1=2313T0 The final pressure P will be given byP2V0=n1+n2RT⇒P=n1+n2RT2V0=3n1RT2V0⇒P=3R2V0n1T=3R2V0P0V0RT02313T0=6926P0
Watch 3-min video & get full concept clarity