Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A hemispherical body is placed in a uniform electric field E. What is the flux linked with curved surface, if field is perpendicular to base in figure.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

2πR2E

b

πR2E/2

c

πR2E

d

0

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let us consider that the given hemispherical body as a closed surface (whose flux is ϕ2 ) In this case, the electric flux linked with the body is zero since the body does not enclose any charges:ϕ=ϕ1+ϕ2=0⇒ϕ1=−ϕ2………………(1)Since the field acts perpendicular to the base, the flux linked with the base is given byϕ2=E×πR2cos⁡180∘=−πR2ETherefore, the flux linked with the curved surface is⇒ϕ1=−ϕ2=−−πR2E=πR2E
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring