A hemispherical bowl just floats without sinking in a liquid of density 1.2 × 103 kg/m3. If outer diameter and the density of the bowl are 1 m and 2 × 104 kg/m3 respectively, then the inner diameter of the bowl will be

Weight of the bowl = mg =Vρg=43πD23−d23ρgwhere D = Outer diameter, d = Inner diameter ρ = Density of bowl Weight of the liquid displaced by the bowl =Vσg=43πD23σ gwhere  σ is the density of the liquid.For the flotation  43πD23σg=43πD23−d23ρg⇒123×1.2×103=123−d232×104By solving we get d = 0.98 m.