A hemispherical bowl just floats without sinking in a liquid of density 1.2 x 103kg/m3. If the outer diameter and the density of the bowl are 1 m and 2×104kg/m3, respectively, then the inner diameter of the bowl will be

Weight of the bowl = mg                             =Vρg=43πD23−d23ρgwhere D = Outer diameter          d = Inner diameter          ρ = Density of bowlWeight of the liquid displaced by the bowlVσg=43πD23σgwhere σ is the density of the liquid. For floatation: 43πD23σg=43πD23−d23ρg⇒123×1.2×103=123−d232×104 By solving, we get d=0.98m .