A hemispherical bowl just floats without sinking in a liquid of density 1.2 × 103kg/m3. If outer diameter and the density of the bowl are I m and 2 x l04kg/m3 respectively, then the inner diameter of the bowl will be

Weight of the bowl = mg  = Vρg = 43π[(D2)3-(d2)3]ρgWhere D = Outer diameter             d = Inner diameter             ρ = Density of bowlWeight of the liquid dispalced by the bowl      = Vσg = 43π(D2)3σgwhere σ is the density of the liquid.For the flotation43π(D2)3σg = 43π[(D2)3-(d2)3]ρg⇒ (12)3×1.2×103 = [(12)3-(d2)3]2×104By solving we get d = 0.98 m.