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A hemispherical bowl of radius R is set rotating about its axis of symmetry. A small body kept in the bowl rotates with the bowl without slipping on its surface. If radius through the body makes with the axis an angle θθ and assuming that the surface of the bowl is smooth, the angular velocity with which bowl is rotating is given by

a
Rgcos⁡θ
b
Rgcos⁡θ
c
gRcos⁡θ
d
gRcos⁡θ

detailed solution

Correct option is C

The different forces on the small body are shown in fig.From figure sin⁡θ=(r/R)……………..(i)Now, Ncos⁡θ=mg ……………………(ii)and Nsin⁡θ=mrω2…………………….(iii)Dividing eq. (iii) by eq. (ii), we gettan⁡θ=rω2g=(Rsin⁡θ)ω2gor sin⁡θcos⁡θ=(Rsin⁡θ)ω2gor ω2=gRcos⁡θ  or  ω=gRcos⁡θ

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