A hemispherical bowl of radius R is set rotating about its axis of symmetry. A small body kept in the bowl rotates with the bowl without slipping on its surface. If radius through the body makes with the axis an angle θ. θ and assuming that the surface of the bowl is smooth, the angular velocity with which bowl is rotating is given by
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a
Rgcosθ
b
Rgcosθ
c
gRcosθ
d
gRcosθ
answer is C.
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Detailed Solution
The different forces on the small body are shown in fig.From figure sinθ=(r/R)……………..(i)Now, Ncosθ=mg ……………………(ii)and Nsinθ=mrω2…………………….(iii)Dividing eq. (iii) by eq. (ii), we gettanθ=rω2g=(Rsinθ)ω2gor sinθcosθ=(Rsinθ)ω2gor ω2=gRcosθ or ω=gRcosθ