A hemispherical glass body of radius 10cm and refractive index 1.5 is silvered on its curved surface. A small air bubble is 6cm below the flat surface inside it along the axis. The position of the image of the air bubble made by the mirror is seen:

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14 cm below flat surface

20 cm below flat surface

16 cm below flat surface

30 cm below flat surface

answer is B.

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Detailed Solution

Given, radius of hemisphere glass R=10cm∴ Focal length f=102=−5cmu=(10−6)=−4cm By using mirror formula 1v+1u=1f ⇒1v+1−4=1−5 ⇒v=20cmApparent height, ha=hrμ1μ2=30×11.5=20cmBelow flat surface

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