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Q.

A hemispherical portion of radius a is removed from the bottom of a cylinder of radius a. The volume of the remaining cylinder is V and its mass is M. It is suspended by a string of length l in a liquid of density ρ where stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. The force on the bottom of the cylinder is

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a

Mg

b

Mg−Vρg

c

Mg+πa2hρg

d

ρg(V+πa2h)

answer is D.

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Detailed Solution

Fat bottom = Fat top +up thrust              =(ρgh).πa2+Vρg=ρg(πa2h+V)
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