A hollow cylinder has a charge q coulomb within it. If ϕ is the electric flux in unit of volt-meter associated with the curved surface B, the flux linked with the plane surface A in unit of volt-metre will be
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a
qε0-ϕ
b
q2ε0
c
ϕ3
d
12qε0-ϕ
answer is D.
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Detailed Solution
Gauss's law states that the net electric flux through any closed surface is equal to the net charge inside the surface divided by ε0· i.e., ϕtotal =qε0Let electric flux linked with surfaces A, B and C are ϕA, ϕB and ϕC , respectively. That isϕtotal =ϕA+ϕB+ϕC Since ϕC=ϕA ∴ 2ϕA+ϕB=ϕtotal =qε0 or ϕA=12qε0-ϕB But ϕB=ϕ (given) Hence, ϕA=12qε0-ϕ