Questions
A hollow disc of inner radius R and outer radius 2R has moment of inertia I about an axis passing through its centre and perpendicular to the plane of the disc. When the disc is melted and recast into a solid disc of same thickness, its moment of inertia about the same axis is
detailed solution
Correct option is D
Massm=π2R2−R2t.ρ=πR12.t.ρ⇒ R1=3 RNow, I=12m2R2+R2=52mR2I1=12mR12=12.m3 R2=32mR2=32.2I5=35ITalk to our academic expert!
Similar Questions
Two discs have mass ratio 1 : 2 and diameter ratio 2 : 1, then find the ratio of their moments of inertia.
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