First slide
Pressure in a fluid-mechanical properties of fluids
Question

A hollow sphere of radius R is made of metal whose specific gravity is ρ . The sphere will float in water if thickness of wall of sphere is (thickness of wall << R)

Moderate
Solution

Given
Radius of hollow sphere =R
Specific gravity= ρ
Now mass of spherical shell
M1= Solid volume of the sphere density of material
M1=4πR2tρ 
Where  M1=Mass of the hollow sphere
t=Thickness of the hollow sphere
While the mass of water having same volume =  Whole volume of the sphere × density of the water
M2=43πR3ρw 
For the floatation of sphere  M1M2
4πR2tρ43πR3ρw 
tρR3ρw=1 g/cm3 
  Thickness tR3ρ   
 

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