First slide
Friction on horizontal surface
Question

A homogeneous chain lies in limiting equilibrium on a horizontal table of coefficient of friction 0.5 with part of it hanging over the edge of the table. The fractional length of the chain hanging down the edge of the table is

Moderate
Solution

\frac{x}{l} = \frac{\mu }{{1 + \mu }}Given\;\mu = 0.5
\frac{x}{l} = \frac{{1/2}}{{1 + 1/2}} = \frac{{1/2}}{{3/2}} = \frac{1}{3}
Fractional length  = 1/3

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