A homogeneous cylinder of mass M and radius R is pulled on a horizontal plane by a horizontal force F acting through its centre of mass. Assuming rolling without slipping the angular acceleration of the cylinder is
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a
3F / 2MR
b
2F / 3MR
c
F / 2MR
d
3F / 4MR
answer is B.
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Detailed Solution
Torque about COM = f R.: FromWe can write , f R = (1/2 m R2) αf = 1/2 m R α------- (1)From Fnet = m ac ,F -f = m ac ---------------- (2)Also, ac = R α ---------------- (3)Solving, α = 2F / 3m R