A homogeneous plate PQRST is as shown in figure. The centre of mass of plate lies at midpoint A of segment QT. Then the ratio of ba is (PQ = PT = b; QR = RS = ST = a)
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a
134
b
132
c
132
d
134
answer is D.
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Detailed Solution
If centre of mass is at Aa2σa2 = σ12absin θ13bsinθ or ba= 134