Q.
A hoop rolls on a horizontal ground without slipping with linear speed v. Speed of a particle P on the circumference of the hoop at angle θ is:
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a
2v sin (θ2)
b
v sin θ
c
2v cos (θ2)
d
v cos θ
answer is A.
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Detailed Solution
vp = v2+v2+2vv cos (180-θ)⇒vp = 2v2[1-cos θ] = 2v sin (θ2)
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