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Questions  

A hoop rolls on a horizontal ground without slipping with linear speed v. Speed of a particle P on the circumference of the hoop at angle θ is:

a
2v sin (θ2)
b
v sin θ
c
2v cos (θ2)
d
v cos θ

detailed solution

Correct option is A

vp = v2+v2+2vv cos (180-θ)⇒vp  = 2v2[1-cos θ]           = 2v sin (θ2)

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Similar Questions

I. Speed of any point on rigid body executing rolling motion can be calculated by the expression ν=rω
where r is the distance of point from instantaneous centre of rotation.
II. Rolling motion of rigid body can be considered as a pure rotation about instantaneous centre of rotation.
Which of the above statement{s} is/are correct? 


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