Q.
Horizontal component of velocity of bomb that is dropped from an aeroplane flying horizontally ….
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a
remains Constant
b
Increases
c
Decreases
d
is Zero
answer is A.
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Detailed Solution
bomb dropped from aeroplane, initial velocity horizontal component=ux acceleration horizontal component=ax=0 equation of motion→sx=uxt+12axt2 substitute, →sx=uxt+0 ⇒sx α t here ux is constant displacement is proportional to the time as the acceleration =0
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