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Questions  

A horizontal force of 100 N is applied a block of mass 10 kg is placed on a rough horizontal surface with a coefficient of kinetic friction, μk=0.5. Find the acceleration of the block.

 (Take g=10ms2 ) 

a
10 ms−2
b
5 ms−2
c
15 ms−2
d
0.5 ms−2

detailed solution

Correct option is B

Here, m = 10 kg, g = 10ms−2, μ = 0.5, F = 100 NForce of friction,f=μN=μmg=0.5×10kg×10ms−2=50NForce that produces accelerationF′=F−f=100N−50N=50Na=F′m=50N10kg=5ms−2

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