First slide
Friction on horizontal surface
Question

A horizontal force of 100 N is applied a block of mass 10 kg is placed on a rough horizontal surface with a coefficient of kinetic friction, μk=0.5. Find the acceleration of the block.

 (Take g=10ms2 ) 

Moderate
Solution

Here, m = 10 kg, g = 10ms2, μ = 0.5, F = 100 N

Force of friction,

f=μN=μmg=0.5×10kg

×10ms2=50N

Force that produces acceleration

F=Ff=100N50N=50N

a=Fm=50N10kg=5ms2

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