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A horizontal force of 100 N is applied a block of mass 10 kg is placed on a rough horizontal surface with a coefficient of kinetic friction, μk=0.5. Find the acceleration of the block. (Take g=10ms−2 )

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a

10 ms−2

b

5 ms−2

c

15 ms−2

d

0.5 ms−2

answer is B.

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Detailed Solution

Here, m = 10 kg, g = 10ms−2, μ = 0.5, F = 100 NForce of friction,f=μN=μmg=0.5×10kg×10ms−2=50NForce that produces accelerationF′=F−f=100N−50N=50Na=F′m=50N10kg=5ms−2

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A horizontal force of 100 N is applied a block of mass 10 kg is placed on a rough horizontal surface with a coefficient of kinetic friction, μk=0.5. Find the acceleration of the block. (Take g=10ms−2 )