First slide

laws

Question

A horizontal narrow glass tube of 100 cm length closed at both ends contains a gas divided in to equal parts by a mercury pellet 10 cm long with the system at $127 ° C$ . Now one side is heated to $227 ° C$ , while the other side is cooled to $27 ° C$ . The distance moved by the mercury pellet in cm is nearly (neglect expansion of glass and mercury)

Easy

A

11.2
B

5.6
C

56.2
D

33.8

Solution

Initially both sides contain same number of moles and finally also they must contain same number of moles. If x is displacement of mercury pellet on the hot side the length of gas column is (45 + x) and on the cold side it is (45 - x). The pressures on both sides are equal and apply PV = nTR for hot side and cold side

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