A horizontal pipe line carries water in a stream line form. At a point along the pipe where the cross-sectional area is 10 cm2, the water velocity is1 m/s and the pressure is 2000Pa. The pressure of water at another point where the cross-sectional area is 5 cm2, is
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a
500Pa
b
50 Pa
c
5Pa
d
5x103Pa
answer is A.
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Detailed Solution
According to equation of continuity A1V1=A2V2 or 10cm2×1m/s=5cm2×v2 ∴ v2=2m/s From Bernoulli's theorem P+12ρv2= constant ∴ P2+12ρv22=P1+12ρv12 or P2+12×103×(2)2=2000+12×103×(1)2 Solving, we get P2=500 Pa