In a horizontal pipe line of uniform area of cross section, the pressure fall by 16 N/m2 between two points separated by distance of 1km . The change in K.E per kg of the oil flowing at these points is (density of oil is 800 kg/m3 )

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2×10−2J/kg

10−2J/kg

4×10−2J/kg

3×10−2J/kg

answer is A.

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Detailed Solution

Kinetic energy per unit mass =p1−p2ρ=16800=2100=2×10−2J/kg

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