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Q.

A horizontal pipe of non-uniform cross section has water flow through it such that the velocity is 3m/sec at a point where the pressure 80 kpa . The pressure at a point where the velocity of flow 5 m/sec is

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a

64,000 pa

b

72,000 pa

c

92,000 pa

d

88,000 pa

answer is B.

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Detailed Solution

p1−p2=ρ2(v22−v12) 80,000−p2=10002(52−32)⇒80,000−p2=500(25−9) ⇒80,000−p2=500×16 p2=80,000−8000=72,000pa
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