A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is $3 .92 \times 10^{- 3} m$ . What must be the least period of these oscillations, so that the object is not detached from the platform
View solution

Question

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is $3 .92 \times 10^{- 3} m$ . What must be the least period of these oscillations, so that the object is not detached from the platform

View solution

Infinity Learn · Accepted Answer

By drawing free body diagram of object during the downward motion at extreme  position, for equilibrium of mass $$Mg-$$ R $$=$$ mA $$(A$$ $$=$$ $$Acceleration)For$$ critical condition R $$=$$ $$0$$ so  $$mg=mA$$⇒$$mg=ma$$ω$$2$$⇒ω$$=g/a=9.83.92$$×$$10$$−$$3=50$$⇒$$T=2$$πω$$=2$$$$π$$$$50=0.1256sec$$

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92 x 10^-3 m . What must be the least period of these oscillations, so that the object is not detached from the Platform?

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92 x 10-3 m . What must be the least period of these oscillations, so that the object is not detached from the Platform?

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92 x 10^-3 m . What must be the least period of these oscillations, so that the object is not detached from the Platform?