The horizontal range and maximum height attained by a projectile are R and H, respectively. If a constant horizontal acceleration a = g/4 is imparted to the projectile due to wind, then its horizontal range and maximum height will be
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a
(R+H),H2
b
R+H2,2H
c
(R + 2H), H
d
(R + H), H
answer is D.
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Detailed Solution
H'=H (as vertical component of acceleration has not changed)R=uxT+12axT2=R+12×g4×4u2sin2θg2=R+u2sin2θ2g=(R+H)