First slide

Projection Under uniform Acceleration

Question

The horizontal range and maximum height attained by a projectile are R and H, respectively. If a constant horizontal acceleration a = g/4 is imparted to the projectile due to wind, then its horizontal range and maximum height will be

Moderate

A

$(R + H), \frac{H}{2}$
B

$(R + \frac{H}{2}), 2 H$
C

(R + 2H),H
D

(R + H),H

Solution

$H = \frac{u^{2} \sin^{2} θ}{2 g}, R = \frac{u^{2} \sin 2 θ}{g} Maximum height will be same because acceleration a = g / 4 is in horizontal direction R^{'} = ucosθT + \frac{1}{2} {aT}^{2} = R + \frac{1}{2} \frac{g}{4} {(\frac{2 usinθ}{g})}^{2} = R + H$

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