Questions
The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is
detailed solution
Correct option is B
Given, R = HRange, R = u2 (2 sinθcosθ)g Height, H = u2sin2θ2gHence, u2(2sinθcosθ)g=u2sin2θ2g 2cosθ=sinθ2⇒ tanθ=4⇒θ=tan-1(4)Talk to our academic expert!
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A ball is thrown with a velocity of u making an angle with the horizontal. Its velocity vector normal to initial vector (u) after a time interval of
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