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The horizontal range of a projectile is 43 times its maximum height. Its angle of projection will be:

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a
45°
b
60°
c
90°
d
30°

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detailed solution

Correct option is D

H=V2sin2⁡θ/2gR=V2sin⁡2θ/g HR=14tan⁡θ H43H=14tan⁡θ θ=30∘


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