The horizontal range R of two projectiles are same when their maximum heights are H1 and H2. The value of R is (assume equal speed of projection)
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a
H1+H22
b
H1H2
c
4H1H2
d
H1+H2
answer is C.
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Detailed Solution
Hint : For same range, sum of angle of projection is 90o.H1=u2sin2θ12g H2=u2sin2θ22gsince R is same⇒θ1+θ2=90∘⇒H1=u2sin2θ12g, H2=u2cos2θ12gMultiplyingH1H2=u4sin2θ1cos2θ14gH1H2=u2sinθ1cosθ12gH1H2=u2sin2θ14g⇒R=4H1H2