A horizontal spring block system of mass M executes simple harmonic motion. When the block is passing through its equilibrium position, an object of mass m is put on it and the two move together. Find the new amplitude
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
MM+mA
b
M+mMA
c
mM+mA
d
M+mmA
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Suppose the velocities in the equilibrium position before and after placing the object m and v and v’, and the amplitudes are A and A’ respectively. By conservation of linear momentum we have(M+m)ω'A'=MωA ⇒M+mA'=MA ⇒A' =MM+mA