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Q.

A horizontal spring-block system of mass 2 kg executes S.H.M. When the block is passing through its equilibrium position, an object of mass I kg is put on it and the two move together. The new amplitude of vibration is (A being its initial amplitude)

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a

23A

b

32A

c

2A

d

A2

answer is .

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Detailed Solution

Conserving momentum: 2V = 3V'⇒ V' = 23VEi = 12m1V12 = 122.V2   ⇒ 12KA2 = V2Ef = 12m2V22 = 12.3.23.23V2 = 23V2⇒12KA'2 = 23V2 = 23Ei(Ei = V2 from above)⇒ 12KA'2 = 23(12KA2)  ⇒ A' = 23A
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