The horizontal and vertical displacement x and y of a projectile at a given time t are given by x = 6t metre and y=8t−5t2  metre. The range of the projectile in metre is:

x=(ucosθ)t=6t y=(usinθ)t−12gt2=8t−5t2 Therefore,        usinθ=8                         ucosθ=6 Range R=u2sin2θ8=u2×2sinθcosθg =2(usinθ)(ucosθ)g =2(8)(6)10=9.6 m