First slide

Second law

Question

A hose directs a horizontal jet of water moving with a velocity of 20 m/sec on to a vertical wall. The cross sectional area of the jet is 5 x 10^–4 m². If the density of water is 10³ kg/m³, find the force on the wall assuming that the water is brought to rest there

Easy

A

100 N
B

200 N
C

300 N
D

400 N

Solution

$\begin{array}{l} F = {Av}^{2} ρ = 5 \times 10^{- 4} \times 400 \times 10^{3} \\ = 200 N \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App