First slide

Projection Under uniform Acceleration

Question

A hose lying on the ground shoots a stream of water upward at an angle of 60° to the horizontal with the velocity of 16 ms^-1. The height at which the water strikes the wall 8 m away is

Easy

A

8.9 m
B

10.9 m
C

12.9 m
D

6.9 m

Solution

$u_{x} = 16 \cos 60 ° = 8 {ms}^{- 1} Time taken to reach the wall = 8 / 8 = 1 s Now u_{y} = 16 \sin 60 ° = 8 \sqrt{3} {ms}^{- 1} h = 8 \sqrt{3} \times 1 - \frac{1}{2} \times 10 \times 1 = 13.86 - 5 = 8.9 m$

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