First slide

Projection Under uniform Acceleration

Question

A hose pipe lying on the ground shoots a stream of water upward at an angle 60⁰ to the horizontal at a speed of 20 ms^-1. The water strikes a wall 20 m away at a height of

Moderate

A

14.64 m
B

7.32 m
C

29.28 m
D

10 m

Solution

$\large y = (\tan \theta )x - \left( {\frac{g}{{2{u^2}{{\cos }^2}\theta }}} \right){x^2}$
$\large y = \sqrt3(20) -( {\frac{{10}}{{2X400X1/4}})\times {(20)^2}$
$\large = 20\sqrt 3 - 20 = 20(\sqrt 3 - 1)$
$\large 20 \times 0.732 = 14.64m$

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