First slide
Radiation
Question

A hot body is placed in cooler surroundings. When the body temperature is 75°C, the rate of cooling is 4°C/ min. When it is 55°C, the rate of cooling is 2°C/ min. The temperature of the surroundings is

Easy
Solution

\large \frac {-d\theta}{dt}\propto (\theta -\theta_0);\;4\propto (75-\theta_0);\;2\propto (55-\theta_0)
\large \frac 42=\frac {75-\theta_0}{55-\theta_0};\;\theta_0=35^0C
 

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