A house directs a horizontal jet of water moving with a velocity of 20 m/s on to a vertical wall. The cross-sectional area of the jet is 5 x 10-4 m2. If the density of water is 1000 kg / m3, the force on the wall assuming that the water comes to rest after striking the wall, is
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a
200 N
b
100 N
c
75 N
d
50 N
answer is A.
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Detailed Solution
See fig.Force exerted on the wall, F=mv−mutHere u = 0, ∴ F=mvtThe mass of water coming out from the jet per second is ml= volume × density 1=(AV)×d1where A= area of cross section of the tubeand d = density of water.∴ F=Adv2 =(5×10−4)×(1000)×(20)2 =200N.