Q.

A house directs a horizontal jet of water moving with a velocity of 20 m/s on to a vertical wall. The cross-sectional area of the jet is 5 x 10-4 m2. If the density of water is 1000 kg / m3, the force on the wall assuming that the water comes to rest after striking the wall, is

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a

200 N

b

100 N

c

75 N

d

50 N

answer is A.

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Detailed Solution

See fig.Force exerted on the wall, F=mv−mutHere u = 0,   ∴ F=mvtThe mass of water coming out from the jet per second is ml= volume × density 1=(AV)×d1where A= area of cross section of the tubeand d = density of water.∴ F=Adv2 =(5×10−4)×(1000)×(20)2 =200N.
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A house directs a horizontal jet of water moving with a velocity of 20 m/s on to a vertical wall. The cross-sectional area of the jet is 5 x 10-4 m2. If the density of water is 1000 kg / m3, the force on the wall assuming that the water comes to rest after striking the wall, is