A house directs a horizontal jet of water moving with a velocity of $$20$$ $$m/s$$ on to a vertical wall. The $$cross-sectional$$ area of the jet is $$5$$ x $$10-4$$ $$m2$$. If the density of water is $$1000$$ kg $$/$$ $$m3$$, the force on the wall assuming that the water comes to rest after striking the wall, is

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Infinity Learn · Accepted Answer

See fig.Force exerted on the wall, $$F=mv$$−mutHere u $$=$$ $$0$$,   ∴ $$F=mvtThe$$ mass of water coming out from the jet per second is $$ml=$$ volume × density $$1=(AV)$$×$$d1where$$ $$A=$$ area of cross section of the tubeand d $$=$$ density of water.∴ $$F=Adv2$$ $$=(5$$×$$10$$−$$4)$$×(1000)×$$(20)2$$ $$=200N$$.

A house directs a horizontal jet of water moving with a velocity of 20 m/s on to a vertical wall. The cross-sectional area of the jet is 5 x 10^-4 m². If the density of water is 1000 kg / m³, the force on the wall assuming that the water comes to rest after striking the wall, is

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A house directs a horizontal jet of water moving with a velocity of 20 m/s on to a vertical wall. The cross-sectional area of the jet is 5 x 10-4 m2. If the density of water is 1000 kg / m3, the force on the wall assuming that the water comes to rest after striking the wall, is

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A house directs a horizontal jet of water moving with a velocity of 20 m/s on to a vertical wall. The cross-sectional area of the jet is 5 x 10^-4 m². If the density of water is 1000 kg / m³, the force on the wall assuming that the water comes to rest after striking the wall, is