First slide

Capacitance

Question

How does the potential difference change with the effect of the dielectric when the battery is kept disconnected from the capacitor?

Easy

A

Increases
B

Decreases
C

Remains constant
D

Becomes zero

Solution

When the dielectric slab is introduced between the plates, the induced surface charge on the dielectric reduces the electric field. The reduction in the electric field results in a decrease in potential difference.
V = Ed = $\frac{E_{0}}{K} d$ = $\frac{V_{0}}{K}$

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