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Q.

How many revolutions doe an electron complete in one second in the first orbit of hydrogen atom

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a

6.57×1015

b

6.57×1013

c

1000

d

6.57×1014

answer is A.

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Detailed Solution

L=nh2π mr2ω=(1)h2π mr22πf=(1)h2π f=6.63×10-344π2mr2 =6.63×10-344(3.14)29.1×10-31(0.53×10-10)2 =6.57×10-15Hz
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