A hydraulic press can lift 100 kg when a mass ‘m’ is placed on the smaller piston. It can lift ________ kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass ‘m’ on the smaller piston.
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answer is 25600.
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Detailed Solution
Using Pascal's Law, same Pressure is transmitted .⇒F1A1=F2A2 Initially, 100gA1=mgA2……….(i)here, A1 is area of larger piston , which will become 16A1 andA2 is area of smaller piston, which will become A216 Finally, Mg16A1=mgA216………(ii)⇒100×16M=116⇒M=25600kg