In hydrogen atom the electron is making 6.6 x 1015 rev/sec. around the nucleus in an orbit of radius o .528 Ao. The magnetic moment (Am2) will be

Given that, v = 6.6 x 1015 rev./sec.and r = 0.528 Ao = 0.528 x 10-10mWe know that, M = i A = (e/T) x A∴M=(ev)×πr2=1⋅6×10−196⋅6×1015×3⋅14×0⋅528×10−102=0⋅925×10−23Am2