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Q.

In hydrogen atom, if the difference in the energy of the electron in n = 2 and n = 3 orbits is E, the ionization energy of hydrogen atom is :

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a

13.2 E

b

7.2 E

c

5.6 E

d

3.2 E

answer is B.

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Detailed Solution

given E=13.6122-132 E=13.69-436 =13.6 x536 ionisation energy is 13.6= E365=7.2 E
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In hydrogen atom, if the difference in the energy of the electron in n = 2 and n = 3 orbits is E, the ionization energy of hydrogen atom is :