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Questions  

In hydrogen atom, if the difference in the energy of the electron in n = 2 and n = 3 orbits is E, the ionization energy of hydrogen atom is :

a
13.2 E
b
7.2 E
c
5.6 E
d
3.2 E

detailed solution

Correct option is B

given E=13.6122-132 E=13.69-436 =13.6 x536 ionisation energy is 13.6= E365=7.2 E

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