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A hydrogen atom in its ground state is irradiated by light of wavelength 970A°. Taking  hc/e=1.237×10−6eV m and the ground state energy of  hydrogen atom as −13.6eV, the number of lines present in the emission spectrum is

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answer is 6 .

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Detailed Solution

Energy of radiation incident =hcλ =12370970 =12.75eVEnergy of Ground state e−  after absorbing 12.75 eV photon is 13.6-12.75=0.85 eVThis  belongs to 4th stateNumber of lines in the emissionSpectrum is nn-12=6
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A hydrogen atom in its ground state is irradiated by light of wavelength 970A°. Taking  hc/e=1.237×10−6eV m and the ground state energy of  hydrogen atom as −13.6eV, the number of lines present in the emission spectrum is