A Hydrogen atom and a Li++ ion are both in the second excited state. If lH and lLi are their respective electronic angular momenta, an EH and ELi their respective energies. then
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a
lH>lLI and EH>ELi
b
lH=lLI and EH
c
lH=lLI and EH>ELi
d
lH
answer is B.
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Detailed Solution
In second excited state n = 3So lH=lLi=3h2πWhile E∝Z2 and ZH=1, ZLi=3SoELi=9EH or EH