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Q.

Hydrogen (H), deuerium (D), singly ionised helium (He)+ and doubly ionised (Li++) all have one electron round the nucleus. Consider n = 2 to n = 1 transition. The wavelength of emitted radiations are λ1,λ2,λ3 and λ4 respectively. Then approximately

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a

λ1=λ2=4λ3=9λ4

b

4λ1=2λ2=2λ3=λ4

c

λ1=2λ2=22λ3=32λ4

d

λ1=λ2=2λ3=3λ4

answer is A.

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Detailed Solution

hcλ=RhCZ2⁡1−14⇒1λ1:1λ2:1λ3:1λ4=1:1:4:9⇒λ1:λ2:λ3:λ4=1:1:14:19
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