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Q.

A hydrogen – like ion having wavelength difference between first line of Balmer and Lymann series is 593  Ao.  Then atomic number of the ion is _____

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a

1

b

2

c

3

d

4

answer is C.

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Detailed Solution

1λ1=z2R 1−122=3RZ241λ1=z2R 122−132=5RZ236Now,  λ2−λ1=365RZ2−43RZ2=8815 RZ2 ∴     88Z215 ×  1.097 ×  107=593 ×  10−10 ⇒   Z=3.
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A hydrogen – like ion having wavelength difference between first line of Balmer and Lymann series is 593  Ao.  Then atomic number of the ion is _____