In Hydrogen spectrum the shortest wavelength in Balmer series is λ . The shortest wavelength in the Brackett series will be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

2λ

4λ

9λ

16λ

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For shortest wavelength in Balmer series, n1=2, n2=∞1λ=R142−1∞⇒λ=4RFor shortest wavelength in Brackett series, n1=4, n2=∞∴1λ'=R142−1∞⇒λ'=16R=4λ