Questions
In Hydrogen spectrum the shortest wavelength in Balmer series is . The shortest wavelength in the Brackett series will be
a
2λ
b
4λ
c
9λ
d
16λ
detailed solution
Correct option is B
For shortest wavelength in Balmer series, n1=2, n2=∞1λ=R142−1∞⇒λ=4RFor shortest wavelength in Brackett series, n1=4, n2=∞∴1λ'=R142−1∞⇒λ'=16R=4λTalk to our academic expert!
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