First slide
Bohr's atom model
Question

In hydrogen-like atom (atomic number A is in a higher excited state of quantum number n. This excited atom can make a transition to first excited state by emitting photons of energies 10.20 eV and 17.00 eV respectively. Alternatively the atom from the same excited state can make a transition to the second excited state by successively emitting two photons of energies 4.25 eV and 5.95 eV respectively. Determine values of n (ionization energy of hydrogen atom = 13.6 eV).

Moderate
Solution

 Given that EnE2=10.2+17.0=27.2eV

 and EnE3=4.25+5.95=10.2eV

E3E2=27.210.2=17eV

1.89Z2=17eV

Z=3

 Now we use 27.2=13.6Z2141n2n=6

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