In a hypothetical Bohr hydrogen, the mass of the electron is doubled. The energy Eo and the radius ro of the firstorbit will be (ao is the Bohr radius)
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a
Eo=−27.2 eV; ro=ao/2
b
Eo=−27.2 eV; ro=ao
c
Eo=−13.6 eV; ro=ao/2
d
Eo=−13.6 eV; ro=ao
answer is A.
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Detailed Solution
Here radius of electron orbit r ∝ 1/m and energy E∝m, where m is the mass of the electron.Hence energy of hypothetical atomEo=2×−13.6eV=−27.2eV and radius ro=ao2