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A 50 Hz a.c. current of crest value 1 A flows through the primary of a transformer. If the mutual inductance between the primary and secondary be 1.5 H, the crest voltage induced in the secondary is

a
75 V
b
150 V
c
225 V
d
300 V

detailed solution

Correct option is D

The current changes from 1 amp to - 1 amp. Hencedi = 1-(-1) = 2amp.dt = (1/ 100)s and M = 1.5H∴e=Mdidt=1⋅5×2(1/100)= 7.5 x 2 x 100 = 300 V

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